Question

A model train with a mass of `8 kg` is moving along a track at `9 (cm)/s`. If the curvature of the track changes from a radius of `21 cm` to `72 cm`, by how much must the centripetal force applied by the tracks change?

Answer 1

Change in centripetal force
`Delta F=21,857.14286" "`Dynes

Explanation:

Given data:
`m=8 " "`kg
`v=9" ""cm/sec"`

`r_1=21" ""cm"`
`r_2=72" ""cm"`

For Centripetal Force

`F=(m*v^2)/r`

`F_1=(m*v^2)/r_1=(8000*9^2)/21=30857.14286`

`F_2=(m*v^2)/r_2=(8000*9^2)/72=9000`

`Delta F=F_1-F_2=21,857.14286" "`Dynes

God bless...I hope the explanation is useful.