A model train with a mass of #9 kg# is moving along a track at #15 (cm)/s#. If the curvature of the track changes from a radius of #46 cm# to #35 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Feb 22, 2017

Answer:

The variation in centripetal force is #=0.14N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

#m=mass=9kg#

#v=0.15ms^-1#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=9*0.15^2/0.46=0.44N#

#F_2=9*0.15^5/0.35=0.58N#

#DeltaF=0.58-0.44=0.14N#