A model train with a mass of #9 kg# is moving along a track at #18 (cm)/s#. If the curvature of the track changes from a radius of #36 cm# to #35 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Jan 24, 2018

Answer:

The change in centripetal force is #=0.023N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The mass is of the train #m=9kg#

The velocity of the train is #v=0.18ms^-1#

The radii are

#r_1=0.36m#

and

#r_2=0.35m#

The variation in the centripetal force is

#DeltaF=F_2-F_1#

The centripetal forces are

#F_1=9*0.18^2/0.36=0.833N#

#F_2=9*0.18^2/0.35=0.81N#

#DeltaF=F_1-F_2=0.833-0.81=0.023N#