# A neutralization reaction between KOH(aq) and H_2SO_4(aq) would give which two products?

$\text{Water and potassium sulfate.........}$
${H}_{2} S {O}_{4} \left(a q\right) + 2 K O H \left(a q\right) \rightarrow {K}_{2} S {O}_{4} \left(a q\right) + 2 {H}_{2} O \left(l\right)$
Of course, in aqueous solution, ${K}_{2} S {O}_{4} \left(a q\right)$ is $2 \times {K}^{+}$, and $S {O}_{4}^{2 -}$..........