Question

A paricle of mass 1 kg is executing shm with an amplitude of 1m and time period π s. The kinetic energy of the particle at the movement when the displacement is 0.8m from the mean position is?

Answer 1

`0.72J`

Explanation:

We know,kinetic energy(`E`) of a particle of mass `m` ,angular frequency `omega` ,amplitude `A` ,at a distance `x` from its mean position is given as,

`E = 1/2 m omega^2(A^2- x^2)`

Given, `m=1 Kg` `A=1m` `omega=(2pi)/T =(2pi)/pi=2`

and, `x=0.8m`

So,`E=1/2*1*2^2(1^2 -0.8^2)=1/2*4*1.8*0.2=0.72J`