Question

A particle moves along the x axis according to the expression x= 2+3t-t2 where x is position in m and t is the time in s find the average acceleration of the particle during the time intervals 0 to 2s ?

Answer 1

Given, expression of position is `x =2 +3t - t^2`

So, velocity time relationship will be `(dx)/(dt) = 3 -2t`

So,velocity at `t=0` is `3 ms^-1`

And, at `t=2` was `(3-2×2)=-1ms^-1`

So,average acceleration = change in velocity/total time taken for the change = `(-1-3)/(2-0)=-2 ms^-2`