# A pendulum on earth with a length of 1.2 m and a mass .25 kg is set in motion. What is its period?

I found $T = 2.2$ seconds
The period $T$ of the pendulum depends on the length $l$ and acceleration of gravity $g$ as:
$T = 2 \pi \sqrt{\frac{l}{g}}$
$T = 2 \pi \sqrt{\frac{1.2}{9.8}} = 2.19 \approx 2.2$ seconds