Question

A plane of mass 50000 kg requires a path of 1500 m to reach 180 km\hr find: the acceleration the engine force?

Answer 1

`5/6\ "m/s"^2` and `"41.67 kN"`

Explanation:

Calculate acceleration by using the equation

`"v"^2 - "u"^2 = "2aS"`

`"a" = ("v"^2 - "u"^2)/("2S") = ((180 × 5/18\ "m/s")^2 - ("0 m/s")^2)/(2 × 1500\ "m") = 5/6\ "m/s"^2`

Force is

`"F = ma = 50000 kg" × 5/6\ "m/s"^2 = 125000/3\ "N" ≈ "41.67 kN"`