Question

A plane traveling at 80 m/s lands on a runway and comes to rest after 10 seconds. What was the distance it traveled down the runway before it stopped?

Answer 1

`400m`

Explanation:

Use the suvat equation for distance,

`s = 1/2(u+v)t`,

where `s` is distance, `u` is initial velocity, `v` is final velocity, and `t` is time.

The distance is what you're trying to find in the question, the initial velocity is given as `80m/s`, and final velocity is nothing (`0m/s`) because it has stopped moving, and the time is given too as `10s`.

Inserting these into the equation gives you

`s = 1/2(80m/s+0m/s)*10s = 400m`