A planet has a perihelion distance of 1 A.U. and a semi major axis of 234.89 A.U. What is it's aphelion distance?

Apr 3, 2017

The aphelion distance is $468.78$AU

Explanation:

Given that the planet follows an elliptical orbit with a semi major axis $a$ and an eccentricity $e$. The perihelion distance is given by $a \left(1 - e\right)$ and the aphelion distance is $a \left(1 + e\right)$.

Substituting the values for perihelion:

$1 = 234.89 \left(1 - e\right)$

$e = \frac{233.89}{234.89}$

So the aphelion distance as:

$234.89 \left(1 + \frac{233.89}{234.89}\right) = 468.78$AU