A positron under goes a displacement r=2i-3j+6k ending with the positron vectors r=3j-4k in meters.what was the positron initial positron vectors?

1 Answer
Mar 5, 2018

Displacement = final position - initial position

Let,the positron's displacement is given by #vec S# and its initial and final positions are expressed as #vec R_1# and #vec R_2# respectively.

So,#vec S = vec R_2 - vec R_1#

So, #vec R_1 = vec R_2 -vec S#

Putting the given values we get,

#vec R_1=3hatj-4hatk -2hati +3hatj -6hatk#

So,#vec R_1=-2hati+6hatj-10hatk#

This was the initial position vector.