# A projectile is launched at an angle of 30 to the horizontal with a speed of 30 m/s. How does the horizontal component of its velocity 1.0 s after launch compare with its horizontal component of velocity 2.0 s after launch?

Jan 2, 2018

Component of velocity in horizontal direction $= 15 \sqrt{3} \frac{m}{s}$

#### Explanation:

In projectile motion, horizontal component of velocity remains constant as there is no acceleration in horizontal direction.

So, Component of velocity in horizontal direction $= v \cos \theta$

Component of velocity in horizontal direction $= 30 \times \cos 30$

Component of velocity in horizontal direction $= 15 \sqrt{3} \frac{m}{s}$

And, horizontal component of velocity$1.0 s$ after launch is equal to its horizontal component of velocity $2.0 s$ after launch.