# A projectile is shot at a velocity of  15 m/s and an angle of pi/6 . What is the projectile's peak height?

${h}_{m} \cong 2 , 867 m$
$\alpha = \frac{\pi}{6} \cdot \frac{180}{\pi} = {30}^{o}$
$\sin {30}^{o} = 0 , 5$
${h}_{m} = \frac{{v}_{i}^{2} \cdot {\sin}^{2} \alpha}{2 \cdot 9 , 81} \text{ maximum height}$
${h}_{m} = \frac{225 \cdot 0 , 25}{19 , 62}$
${h}_{m} \cong 2 , 867 m$