# A projectile is shot at a velocity of  5 m/s and an angle of pi/8 . What is the projectile's peak height?

${h}_{m} = 0 , 186603732679 m$
h_m=(v_i² sin² theta)/(2*g)
$\theta = \frac{\cancel{\pi}}{8} \cdot \frac{180}{\cancel{\pi}} = 22 , 5$
${h}_{m} = \frac{{5}^{2} \cdot 0 , 14644609407}{2 \cdot 9 , 81}$
${h}_{m} = 0 , 186603732679 m$