# A projectile is shot at an angle of pi/12  and a velocity of 46 m/s. How far away will the projectile land?

Dec 29, 2015

The projectile will fall $107.8 m$ far

#### Explanation:

Consider the two equation of speed
$s \left(x\right) = v t$ with v=cos15°
$s \left(y\right) = v t - \frac{1}{2} a {t}^{2}$ with v=sin15°
Find the time when $s \left(y\right) = 0$, so $t \left(v - \frac{1}{2} a t\right) = 0$
$t \left(f a l l\right) = 2 \frac{v}{g} = 2.43 s$ and use this value in the horizontal equation
s(t)=(46cos15°)*2.43=107.8m