# A projectile is shot at an angle of pi/12  and a velocity of 72 m/s. How far away will the projectile land?

$= \frac{{u}^{2} \times \sin 2 \alpha}{g} = \left({72}^{2} \times \sin \frac{2 \times \frac{\pi}{12}}{9.8}\right) m \approx 264.5 m$