Question

A projectile is shot at an angle of `pi/3` and a velocity of `3 m/s`. How far away will the projectile land?

Answer 1

`x_"max"=0,79" m"`

Explanation:

`alpha=pi/3" ; "2*alpha=(2pi)/3" ;" sin ((2pi)/3)=0,866`
`v_i=3" "m/s`

`x_"max"=(v_i^2*sin 2alpha)/g`

`x_"max"=(3^2*0,866)/(9,81)`

`x_"max"=0,79" m"`