# A projectile is shot at an angle of pi/3  and a velocity of  72 m/s. How far away will the projectile land?

The distance is $457.64 m$

#### Explanation:

We know that the distance is given by

$R = \frac{{v}^{2} \sin 2 \theta}{g}$

$= \frac{{72}^{2} \sin \left(2 \cdot \frac{\pi}{3}\right)}{9.81}$

$= 457.64 m$