Question

A projectile is shot at an angle of `pi/6` and a velocity of `1 m/s`. How far away will the projectile land?

Answer 1

0.088 m

Explanation:

`"Initial Velocity"` `u=1 m/s`
`"Angle of Projection"` `theta=pi/6`

`"Horizontal Range"` `R=(u^2sin2theta)/g`
`R=(1^2sin(2pi/6))/9.8=sin(pi/3)/9.8=sqrt3/(2xx9.8)`
`R=0.088 m`