# A projectile is shot at an angle of pi/6  and a velocity of  1 m/s. How far away will the projectile land?

Oct 4, 2017

0.088 m

#### Explanation:

$\text{Initial Velocity}$ $u = 1 \frac{m}{s}$
$\text{Angle of Projection}$ $\theta = \frac{\pi}{6}$

$\text{Horizontal Range}$ $R = \frac{{u}^{2} \sin 2 \theta}{g}$
$R = \frac{{1}^{2} \sin \left(2 \frac{\pi}{6}\right)}{9.8} = \sin \frac{\frac{\pi}{3}}{9.8} = \frac{\sqrt{3}}{2 \times 9.8}$
$R = 0.088 m$