# A projectile is shot at an angle of pi/6  and a velocity of  24 m/s. How far away will the projectile land?

The projectile will land $50.9 m$ far.
Find the time t when the projectile lands, with the vertical equation $s \left(y\right) = v t - \frac{1}{2} a {t}^{2} = 0$; $t = 2 \frac{v}{g}$ with v=vsin30°
So $t \left(f a l l\right) = 2.45 m$
$s \left(x\right) = v t$ with v=vcos30° and $t = t \left(f a l l\right)$
s(t)=(vcos30°)*(t(fall))=50.9m