# A projectile is shot at an angle of pi/6  and a velocity of  8 m/s. How far away will the projectile land?

##### 1 Answer
Jan 2, 2016

The projectile will land $5.68 m$ far.

#### Explanation:

Find the time when the projectile lands with the vertical equation $v t - \frac{1}{2} a {t}^{2} = 0$ so $t \left(v - \frac{1}{2} a t\right) = 0$ t(fall)=2v/g=(2vsin30°)/g=0.82s
We use this value in the horizontal equation $s \left(x\right) = v \cdot t \left(f a l l\right)$
So s=vcos30°*t(fall)=5.68m