# A projectile is shot at an angle of pi/8  and a velocity of  12 m/s. How far away will the projectile land?

Dec 12, 2016

x_("max")=10.38" meters"

$\text{rounded two decimal place}$

#### Explanation:

$\text{the maximum distance can be calculated by formula :}$

${x}_{\text{max}} = \frac{{v}_{i}^{2} \cdot \sin 2 \alpha}{g}$

$\text{where " v_i " is initial velocity and " alpha" angle}$

$g = 9.81 \frac{N}{k g}$

${x}_{\text{max}} = \frac{{12}^{2} \cdot \sin \cancel{2} \cdot \frac{\pi}{\cancel{8}}}{9.81}$

${x}_{\text{max}} = \frac{144 \cdot \sin \left(\frac{\pi}{4}\right)}{9.81}$

x_("max")=10.38" meters"