A projectile is shot from the ground at a velocity of #6 m/s# and at an angle of #(3pi)/4#. How long will it take for the projectile to land?

1 Answer
Dec 26, 2015

Answer:

#0.87"s"#

Explanation:

Use the equation of motion:

#v=u+at#

Considering the vertical component of velocity:

This becomes:

#0=vsintheta-"g"t#

#:.0=vsintheta-"g"t#

#:.t=(vsintheta)/g#

Converting radians to degrees:

#2pi=360^@#

#:.pi=360/2=180^@#

#:.(3pi)/4=(3xx180)/4=135^@=theta#

#t=(6sin((3pi)/(4)))/(9.8)#

#t=(6xx0.707)/9.8=0.433"s"#

This is the time to reach the zenith so the total time of flight will be #2xx0.433=0.866"s"#