# A projectile is shot from the ground at an angle of #(5 pi)/12 # and a speed of #5 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?

##### 1 Answer

Jul 4, 2018

The distance is

#### Explanation:

The equation of the trajectory of the projectile in the vertical plane,

The initial velocity is

The angle of projection is

The acceleration due to gravity is

Therefore,

The highest point is reached when

And

The highest point is

The distance from the stat¡rting point is

graph{(3.732x-2.926x^2) [-0.988, 2.43, -0.128, 1.581]}