A projectile is shot from the ground at an angle of #(5 pi)/12 # and a speed of #5 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?
1 Answer
Jul 4, 2018
The distance is
Explanation:
The equation of the trajectory of the projectile in the vertical plane,
The initial velocity is
The angle of projection is
The acceleration due to gravity is
Therefore,
The highest point is reached when
And
The highest point is
The distance from the stat¡rting point is
graph{(3.732x-2.926x^2) [-0.988, 2.43, -0.128, 1.581]}