# A projectile is shot from the ground at an angle of #pi/12 # and a speed of #7 /18 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?

##### 3 Answers

distance from starting point is

#### Explanation:

Range,

When the particle reaches its maximum height, the distance from starting point will be

[Take

#### Explanation:

We're asked to find the distance from the launch point a projectile is when it reaches its maximum height.

We can use the equation

to find the maximum height

When the particle is at its maximum height, the instantaneous velocity

The initial

Plugging in known values, we have

To find the horizontal distance covered

The time

Rearranging this equation and plugging in known values:

Thus, we have

The distance from the starting point is thus

THe distance is

#### Explanation:

Resolving in the vertical direction

initial velocity is

Acceleration is

At the maximum height,

We apply the equation of motion

to calculate the time to reach the greatest height

The greatest height is

Resolving in the horizontal direction

To find the horizontal distance, we apply the equation of motion

The distance from the starting point is