A projectile is shot from the ground at an angle of #pi/4 # and a speed of #16 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?

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Answer 1 · 2016-04-19T12:17:10

#x=13,01 " meters"#
#y=6,52" meters"#

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#t_m=(v_i*sin pi/4)/g#

#t_m=(16*0,707)/(9,81)#

#t_m=1,15" sec"#

#x=v_i*cos pi/4*t_m#

#x=16*1,15*0,707#

#x=13,01 " meters"#

#y=v_i*sin pi/4*t_m-1/2*g*t_m^2#

#y=16*0,707*1,15-1/2*9,81*(1,15)^2#

#y=13,01-6,49#

#y=6,52" meters"#