# A projectile is shot from the ground at an angle of #pi/6 # and a speed of #25 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?

##### 1 Answer

#### Explanation:

The velocity of projection of the projectile

The angle of projection of the projectile

**The horizontal component of velocity of projection**

**TheVertical component of velocity of projection**

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Assuming the ideal situation where gravitational pull is the only force acting on the body and no air resistance exists , we can easily proceed for various calculation using equation of motion under gravity.

**CALCULATION**

Let the projectile reaches its maximum height **H** m after **t** s of its start.

**The final vertical component** of its velocity at maximum height will be **zero**

So we can write

Again

During

Hence the projectil's distance ( **D** ) from starting point to the maximum point of its ascent is given by

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