Question

A projectile is shot from the ground at an angle of `pi/8` and a speed of `4 m/s`. When the projectile is at its maximum height, what will its distance from the starting point be?

Answer 1

`x_m=1,15 " m"`

Explanation:

`x_m=(v_i^2*sin 2alpha)/g`
`v_i=4 " "m/s`

`alpha=pi/8;" "2*pi/8=pi/4 " "sin( pi/4)=sqrt2/2`

`x_m=(4^2*sqrt2/2)/(9,81)`

`x_m=(8sqrt2)/(9,81)`

`x_m=1,15 " m"`