A projectile is shot from the ground at an angle of #pi/8 # and a speed of #5 /8 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?
The distance is
The maximum height is when the vertical component of the velocity
We use the equation,
This is the time to reach the maximum height.
To, get the horizontal distance from the starting point, we multiply by the horizontal component of the velocity.