A rifle is aimed horizontally at a target 50 m away. The bullet hits the target 2.0 cm below the aim point. What was the bullet's flight time, and the speed it left the barrel?

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Michael Share
Nov 17, 2015

Answer:

#(a).#

#0.064"s"#

#(b).#

#781.2"m/s"#

Explanation:

#(a).#

To get the time of flight we consider the vertical component of motion:

#s=1/2"g"t^2#

#:.t=sqrt((2s)/(g))#

#t=sqrt((2xx0.02)/(9.8))#

#t=0.064"s"#

#(b).#

The horizontal component of velocity is constant so:

#v=s/t=50/0.064=781.2"m/s"#

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