Question

A rotating liquid forms a surface in the form of paraboloid.The surface is 2m deep at the centre and 10m across.Obtain an equation of the surface?

Answer 1

`(pia)/(6h^2)(a^2 + 4h^2)^(3/2) - a^3`

Explanation:

Where a = radius at height h
See also:
http://mathworld.wolfram.com/Paraboloid.html

and
http://tutorial.math.lamar.edu/Classes/CalcIII/QuadricSurfaces.aspx