A sample of an ideal gas has a volume of 2.34 L at 279 K and 1.10 atm. What is the pressure when the volume is 1.78 L and the temperature is 304 K?

1 Answer
May 8, 2016

Answer:

Pressure = #1.6 atm#

Explanation:

Use the formula #(P_1V_1)/T_1 = (P_2V_2)/T_2#, where #P_1# is the initial pressure, #V_1# is the initial volume, and #T_1# is the initial temperature. And #V_2\, P_2\, T_2# are the final values (with the variable you're trying to find!)

Substitute the values into the formula.

#((1.10atm)(2.34L))/(279K)= ((P_2)(1.78L))/(304K)#

#(304)(1.10)(2.34) = (P_2)(1.78)(279)#

#782.5 = 496.6 (P_2)#

#P_2 = 1.6 atm#