# A sample of an ideal gas has a volume of 2.34 L at 279 K and 1.10 atm. What is the pressure when the volume is 1.78 L and the temperature is 304 K?

May 8, 2016

Pressure = $1.6 a t m$

#### Explanation:

Use the formula $\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$, where ${P}_{1}$ is the initial pressure, ${V}_{1}$ is the initial volume, and ${T}_{1}$ is the initial temperature. And ${V}_{2} \setminus , {P}_{2} \setminus , {T}_{2}$ are the final values (with the variable you're trying to find!)

Substitute the values into the formula.

$\frac{\left(1.10 a t m\right) \left(2.34 L\right)}{279 K} = \frac{\left({P}_{2}\right) \left(1.78 L\right)}{304 K}$

$\left(304\right) \left(1.10\right) \left(2.34\right) = \left({P}_{2}\right) \left(1.78\right) \left(279\right)$

$782.5 = 496.6 \left({P}_{2}\right)$

${P}_{2} = 1.6 a t m$