A sample of gas contains 0.2000 mol of CH4(g) and 0.4000 mol of O2(g) and occupies a volume of 20.3 L. The following reaction takes place: CH4(g) + 2O2(g)CO2(g) + 2H2O(g) Calculate the volume of the sample after the reaction takes place in liters?

assume the temperature and pressure remain constant.

1 Answer
Mar 8, 2018

You gots....

#underbrace(CH_4(g) + 2O_2(g))_"20 litre volume" rarr underbrace(CO_2(g) + 2H_2O(g))_"20 litre volume"#

Explanation:

Now there are THREE moles of gaseous product, and THREE moles of GASEOUS reactant....given stoichiometric reaction, and CONSTANT #T# and #P#, the volume expressed by the products will be PRECISELY the same as expressed by the reactants...