A sample of gas has a volume of 240. L at 4.00 atm of pressure and a temperature of 1091K. What is the volume at STP?

Feb 17, 2017

$\text{Volume = 240.219981669L}$

Explanation:

Recall the gas law

$P V = n R T$

First we need to find moles of gas and then calculate its volume at STP

So moles of gas or n =

$n = \frac{P V}{R T}$

Solve the equation using formula

$n = \text{(4atm * 240L)"/"(0.0821L * 1091K)}$

n = 960/89.5711"

$n = 10.7177426648 m o l$

The volume of 1mol of any gas = 22.4L

Therefore volume of $10.7177426648 \text{moles}$
$= 10.7177426648 \text{moles} \cdot 22.4134 L = 240.219981669$

But lets still prove it

Volume of 10.7177426648moles in STP
Temperature at STP = ${0}^{o} C \mathmr{and} 273 K$
Pressure at $S T P = 1 a t m$

$V = 10.7177426648 \cdot 0.0821 \cdot \text{273K"/"1atm}$

$V = \frac{240.219981669}{\text{1atm}}$

$\text{Volume = 240.219981669L}$