# A sample of nitrogen gas has a volume of 15mL at a pressure of 0.50 atm. What is the pressure if the volume is changed to 30.0mL?

Aug 12, 2016

That sample of gas has a new pressure of $0.25 a t m$

#### Explanation:

The answer can be determined by using Boyle's Law:

Let's identify our known and unknown variables.

color(brown)("Knowns:"
${P}_{1}$= 0.50 atm
${V}_{1}$= 15 mL
${V}_{2}$= 30.0 mL

color(blue)("Unknowns:"
${P}_{2}$

Rearrange the equation to solve for the final pressure by dividing both sides by ${V}_{2}$ to get ${P}_{2}$ by itself like this:

${P}_{2} = \frac{{P}_{1} \times {V}_{1}}{V} _ 2$

Plug in your given values to obtain the final pressure:

${P}_{2} = \left(0.50 \setminus a t m \times 15 \setminus \cancel{\text{mL")/(30.0\cancel"mL}}\right)$ = $0.25 a t m$