# A sample of NO_2 occupies a volume of 2.3 L at 740 mm Hg. What volume would result if the pressure were increased to 760 mm Hg?

From Boyle's Law, ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$, if $\text{temperature}$ and $\text{amount}$ of gas are constant.
${V}_{2} = \frac{{P}_{1} {V}_{1}}{P} _ 2 = \frac{740 \cdot m m \cdot H g \times 2.3 \cdot L}{760 \cdot m m \cdot H g}$