A seagull diving towards a stone beach at an angle of 60 degrees to the vertical releases a clam from a height of 100 meters. The clam hits the beach seconds later. To the nearest tenth of a 2.32 m/s what was its speed when it was released?
square of final speed = square of initial speed + 2 g (distance),
in the vertical direction..
If v is the speed of the bird, flying at
the magnitude of the component velocity, in the vertical direction, is
I assume that the clam hits the ground at 2.32 m/s, in the vertical
direction, nearly. Then,