Question

A ship travels 60 mi due east, then adjust its course 15° northward. After traveling 80 mi in that direction, how far is the ship from its point of departure?

Answer 1

`118.56` miles (approximately)

Explanation:

Cosine Law:
`color(white)("XXX")c^2=a^2+b^2-2ab * cos(C)`

The situation is as pictured below:

`c^2 = 60^2+80^2 - 2(60)(80)cos(245^@)`

and, using a calculator:
`c~= 118.56`