A solid disk, spinning counter-clockwise, has a mass of #12 kg# and a radius of #6 m#. If a point on the edge of the disk is moving at #8 m/s# in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

1 Answer
Mar 4, 2017

Answer:

#omega = 1.33rads^-1#

#p = 16Nms#

Explanation:

Angular velocity is given by the equation

#omega = v/r = (8ms^-1)/(6m) = 1.33rads^-1#

It is in the units radians per second, or #rads^-1#.

Angular momentum is the product of angular velocity and mass, much like linear momentum is the product of linear velocity and mass, so

#p = momega = 12 xx 1.33 = 16Nms#