Question

A solution contain 900 gm water and 90 gm glucose calculate mole fraction of 60th glucose of water?

Answer 1

`chi_"glucose"=9.90xx10^-3`

Explanation:

`chi_"glucose"="Moles of glucose"/"Moles of glucose + moles of water"`

`=((90*g)/(180.16*g*mol^-1))/((90*g)/(180.16*g*mol^-1)+(900*g)/(18.01*g*mol^-1))=9.90xx10^-3`

So what is `chi_"water"`? You should be able to answer pdq...

I do not know what you mean by 60th glucose of water....