# A solution contains 85.0 g of NaNO_3, and has a volume of 750 mL. What is the molarity of the solution?

Molar mass of $N a N {O}_{3} = 23 + 14 + 3 \times 16 = 85 g m o {l}^{-} 1$
750 mL Solution contains 85g =$85 g \times \frac{1}{85 g m o {l}^{-} 1} = 1 m o l$
molarity = no of mole per Liter=$\frac{1}{750} \times 1000 m = 1.33 m$