# A spring with a constant of 4 (kg)/(s^2) is lying on the ground with one end attached to a wall. An object with a mass of 4 kg  and speed of  8 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?

Jun 19, 2016

It will compress $8 m$.

#### Explanation:

Mass of object =4 kg
Velocity=8m/s

$K E = \frac{1}{2} m {v}^{2}$
$K E = 128 j$

Since ,energy is always conserved.

Spring potential energy = kinetic energy of that body

$P E = \frac{1}{2} K {X}^{2}$
128=2 × X^2
$64 = {x}^{2}$

$X = 8 m$