# A square has sides of length s+3. What is the area of the square?

Dec 1, 2016

$A = {s}^{2} + 6 s + 9$

#### Explanation:

The formula for the Area of a square is:

$A = {l}^{2}$ or $A = l \cdot l$ Where $A$ is the area of the square and $l$ is the length of the side of a square.

For this problem we can substitute $s + 3$ for $l$ and solve:

$A = \left(s + 3\right) \cdot \left(s + 3\right)$

$A = \left(s \cdot s\right) + \left(3 \cdot s\right) + \left(3 \cdot s\right) + \left(3 \cdot 3\right)$

$A = {s}^{2} + \left(3 + 3\right) \cdot s + 9$

$A = {s}^{2} + 6 s + 9$