Question

A squirrel jumps into the air with a velocity of 7 m/s at an angle of 20°. What is the maximum height reached by the squirrel?

Answer 1

`"29.2 cm"`

Explanation:

Maximum height is given by the formula

`"H" = ("u"^2\ sin^2theta)/("2g")`

`"H" = (("7 m/s")^2 × sin^2(20°))/(2 × "9.8 m/s"^2) ≈ "0.292 m ≈ 29.2 cm"`