# A standard number cube is tossed. What is the probability that the number will be less than or equal to 3?

Mar 10, 2018

$P \left(3 \text{ or less on a die}\right) = \frac{3}{6} = \frac{1}{2}$

#### Explanation:

To determine the probability of an event happening, there are two values you need to determine first.

1. How many possible outcomes are there altogether?
In this case with a toss of the die, there are $6$ outcomes, being the numbers from $1$ to $6$.

2. Of the possible outcomes how many of them will meet our conditions? IN this case we want a number equal to or less than $3$, ... the numbers $1 , 2 , 3$. There are $3$ desired outcomes.

$\text{Probability" = "number of desirable outcomes"/"total number of possible outcomes}$

$P \left(3 \text{ or less on a die}\right) = \frac{3}{6} = \frac{1}{2}$

Write a probability as a fraction and give in its simplest form.

Mar 10, 2018

$\frac{1}{2}$

#### Explanation:

assuming that the numbers on the standard number cube are $1 - 6$, there are $6$ possible numbers to get.

the numbers less than or equal to $3$, in the range $1 - 6$, are $1 , 2$ and $3$.

this means that there are $3$ possible numbers to get that are less than or equal to $3$.

probability = number of outcomes possible / total number of outcomes

$\frac{3}{6} = \frac{1}{2}$