A steel cylinder has a weight density of #"0.456 lb/in"^3"#. If the volume of the cylinder is #"123.4 in"^3"#, what is the weight?

Question

1776 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-25T05:56:38

#"Density" (rho)="Mass"/"Volume"#

And thus #"Mass"# #-=# #"Volume"# #xx# #rho#

And we are given both volume and density.

#=0.456*lb*cancel"inch"^-3xx123.4*cancel"inch"^3#

#~=50*lbs#

Answer 2 · 2017-02-25T06:07:55

#"Weight"=56.27# #"lbs"#

Note the formula

#color(blue)("Density"=("Mass")/("Volume")#

Now lets put in everything we know in the formula

#rarr0.456*("lb")/("in"^3)=("Mass")/(123.4*"in"^3)#

#rarr"Mass"=0.456*("lb")/cancel("in"^3)* 123.4*cancel"in"^3#

#color(green)(rArr"Mass"=56.27# #color(green)("lbs"#