# A steel cylinder has a weight density of "0.456 lb/in"^3". If the volume of the cylinder is "123.4 in"^3", what is the weight?

Feb 25, 2017

$\text{Density" (rho)="Mass"/"Volume}$

#### Explanation:

And thus $\text{Mass}$ $\equiv$ $\text{Volume}$ $\times$ $\rho$

And we are given both volume and density.

$= 0.456 \cdot l b \cdot {\cancel{\text{inch"^-3xx123.4*cancel"inch}}}^{3}$

$\cong 50 \cdot l b s$

Feb 25, 2017

$\text{Weight} = 56.27$ $\text{lbs}$

#### Explanation:

Note the formula

$\textcolor{b l u e}{\text{Density"=("Mass")/("Volume}}$

Now lets put in everything we know in the formula

$\rightarrow 0.456 \cdot \left({\text{lb")/("in"^3)=("Mass")/(123.4*"in}}^{3}\right)$

$\rightarrow {\text{Mass"=0.456*("lb")/cancel("in"^3)* 123.4*cancel"in}}^{3}$

color(green)(rArr"Mass"=56.27 color(green)("lbs"