Question

A steel tank with a volume of 9.583 L contains `N_2` gas under a pressure of 4.972 atm at 31.8°C. How many moles of `N_2` are in the tank?

Answer 1

`n~=2*mol`

Explanation:

For the old Ideal Gas equation, `n=(PV)/(RT)`...

And so `n=(4.972*atmxx9.583*L)/(0.0821*(L*atm)/(K*mol)*305*K)`

`=1.90*mol`