A sum of money was divided between A and B so that A's share was to B's share as 5 is to 3. Also, A's share exceeded 5/9 of the whole sum by $50. What was each share? 1 Answer Dec 15, 2016 A has $450 and B has $270 Explanation: Let A's share be $5 x$and B's share be $3 x$. As such the whole sum of money is $5 x + 3 x = 8 x$and $\frac{5}{9}$of whole sum is $\frac{5}{9} \times 8 x = \frac{40}{9} x$. As A's share exceeds $\frac{40}{9} x$by $50,

we have $5 x - \frac{40}{9} x = 50$ and multiplying each term by $9$, we get

$45 x - 40 x = 50 \times 9$

or $5 x = 450$

or $x = \frac{450}{5} = 90$

Hence A has 90xx5=$450 and B has 90xx3=$270.