A syringe has a certain amount of gas trapped in it. The plunger is originally at 8.02 cm^3 and the gas has a pressure of 716 torr. What would the pressure be if the volume were decreased to .089 cm^3?

Constant room temperature

Enter answer in scientific notation, using the format 6.00e3 with e representing 10 and the number to the right of 3 being the exponent.

1 Answer
Meave60
May 10, 2018

The final pressure would be #6.5xx10^4# #"Torr"#.

Explanation:

This is an example of Boyle's law, which states that the volume of a given amount of gas held at constant temperature varies inversely with the applied pressure when the temperature and mass are constant. The equation for this law is:

#"P_1V_1=P_2V_2#

Known

#P_1="716 Torr"#

#V_1="8.02 cm"^3"#

#V_2="0.089 cm"^3"#

Unknown

#P_2#

Solution

Rearrange the equation to isolate #P_2# Plug in the known values and solve.

#P_2=(P_1V_1)/V_2#

#P_2=(716"Torr"xx8.02color(red)cancel(color(black)("cm"^3)))/(0.089color(red)cancel(color(black)("cm"^3)))="65 000 Torr"# (rounded to two significant figures)

#"65 000 Torr"=6.5xx10^4# #"Torr"#

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